Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 41

Answer

$y=2$.

Work Step by Step

The given equation is $\Rightarrow \sqrt{2y}-\sqrt{y+2}=0$ Add $\sqrt{y+2}$ to both sides. $\Rightarrow \sqrt{2y}=\sqrt{y+2}$ Square both sides. $\Rightarrow 2y=y+2$ Subtract $y$ from both sides. $\Rightarrow 2y-y=2$ Simplify. $\Rightarrow y=2$ Check $y=2$. $\Rightarrow \sqrt{2(2)}-\sqrt{2+2}=0$ $\Rightarrow \sqrt{4}-\sqrt{4}=0$ $\Rightarrow 0=0$ True.
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