Answer
There are no extraneous solutions.
Work Step by Step
$y=\sqrt 2y$
With $y=0$ then $0=\sqrt 2(0)$
$0 = 0$
With $y=2$ then $2=\sqrt 2*2$
$2=2$
Hence, there are no extraneous solutions.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 27
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