Answer
$n=3$ is extraneous.
Work Step by Step
$n=\sqrt 12-n$
With $n=-4$ then $-4=\sqrt 12-(-4)$
$-4\ne4$
With $n=3$ then $3=\sqrt 12-(3)$
$3=\sqrt9$
$3=3$
Hence, $n=-4$ is extraneous.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 26
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