Answer
A: $\sqrt 13$ + 2
B: $\sqrt 6$ - $\sqrt 3$
C: $\sqrt 5$+$\sqrt 10$
Work Step by Step
We are asked to find the conjugate of each given expression. To find the conjugate of a binomial, we change the sign of the second term of the given expression.
A:
In this given expression, 2 is being subtracted from $\sqrt 13$. To find its conjugate, we will add 2 to $\sqrt 13$.
$\sqrt 13$-2 --> $\sqrt 13$+2
B:
We notice that $\sqrt 3$ is being added to $\sqrt 6$.
Conjugation: $\sqrt 6$+$\sqrt 3$ --> $\sqrt 6$-$\sqrt 3$.
C:
In the last expression, $\sqrt 10$ is being subtracted from $\sqrt 5$. Therefore, to find its conjugate, we will add $\sqrt 10$ to $\sqrt 5$.
