Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Lesson Check - Page 629: 6

Answer

$2\sqrt7-4$

Work Step by Step

$\frac{6}{\sqrt 7 +2}$ Multiply the equation with $\frac{\sqrt 7 -2}{\sqrt 7 -2}$ $=\frac{6(\sqrt 7 -2)}{7-4}$ $=\frac{6\sqrt 7-12}{3}$ $=2\sqrt7-4$
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