Answer
$41-12\sqrt 5$
Work Step by Step
We are given:
$(\sqrt 5-6)^2$
$=(\sqrt 5)^2-2\sqrt 5.6+6^2$
$=41-12\sqrt 5$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Lesson Check - Page 629: 4
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