Answer
$\omega_S=15 rad/s$
$\omega_R=3 rad/s$
Work Step by Step
We can determine the required angular velocity as follows:
$r_{A}\omega_S=r_{O/H} \omega_H$
This can be rearranged as:
$\omega_S=\frac{0.15}{0.05}(5)=15 rad/s$
We know that
$r_R \omega_R=r_{O/H}\omega_H$
This can be rearranged as:
$\omega_R=\frac{r_{O/H}}{r_R}\omega_H$
We plug in the known values to obtain:
$\omega_R=\frac{0.15}{0.25}(5)$
$\implies \omega_R=3 rad/s$
