Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.6 - Instantaneous Center of Zero Velocity - Problems - Page 372: 101

Answer

$\omega_R=4 rad/s$

Work Step by Step

The required angular velocity can be determined as follows: We know that $v_C=\omega_A r_A~~~$[eq(1)] and $v_R=\omega_A r_B=\omega_R r_{IC/R}~~~$[eq(2)] Dividing eq(1) by eq(2), we obtain: $\frac{v_C}{v_R}=\frac{r_A}{r_B}$ We plug in the known values to obtain: $\frac{0.9}{v_R}=\frac{0.075}{0.15}$ This simplifies to: $v_R=1.8m/s$ Now $\omega_R=\frac{v_R}{r_{IC/R}}$ We plug in the known values to obtain: $\omega_R=\frac{1.5}{0.45}$ This simplifies to: $\omega_R=4 rad/s$
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