Answer
$\omega_A=6 rad/s \circlearrowright$
Work Step by Step
We can determine the required angular velocity as follows:
$v_c=\omega_CD r_{CD}$
$\implies v_C=3(0.4)=1.2m/s$
We know that
$v_C=\omega_{A}r_{IC/O}$
We plug in the known values to obtain:
$1.2=0.2\omega_A$
This simplifies to:
$\omega_A=6 rad/s \circlearrowright$
