Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.6 - Motion of a Projectile - Problems - Page 49: 76

Answer

$v_{sp}=5.11$ m/s

Work Step by Step

We solve for the average speed as follows: $S_{ToT}=S_{AB}+S_{BC}+S_{CA}$ $S_{ToT}=20(\frac{\pi}{2})+\sqrt{20^2+30^2}+30+20$ $S_{ToT}=117.47$ m $t_{Tot}=t_{AB}+t_{BC}+t_{CA}$ $t_{Tot}=5+8+10$ $t_{Tot}=23$ s $v_{sp}=\frac{S_{Tot}}{t_{Tot}}=\frac{117.47}{23}=5.11$ m/s
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