Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.6 - Motion of a Projectile - Problems - Page 49: 69

Answer

$|a|=5.31$ m/s$^2$ $\alpha=\cos^{-1}(0.6022)=53^{\circ}$ $\beta=\cos^{-1}(0.7984)=37^{\circ}$ $\gamma=\cos^{-1}(0)=90^{\circ}$

Work Step by Step

$v(t)=0.8t^2 i + 12t^{1/2} j + 5 k$ $a=\frac{dv}{dt}=1.6t i + 6t^{-1/2} j$ When $t=2$ s, $a=3.2i + 4.243j$ $|a|=\sqrt{(3.2)^2+(4.243)^2}=5.31$ m/s$^2$ $u_o=\frac{a}{|a|}=0.6022i+0.7984j$ $\alpha=\cos^{-1}(0.6022)=53^{\circ}$ $\beta=\cos^{-1}(0.7984)=37^{\circ}$ $\gamma=\cos^{-1}(0)=90^{\circ}$
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