Answer
$v_{sp}=4.28$ m/s
Work Step by Step
We solve for the average speed as follows:
$S_T=\frac{1}{4}(2\pi)(10)+15+\frac{1}{4}(2\pi(5))=38.56$
$v_{sp}=\frac{S_T}{t}=\frac{38.56}{2+4+3}=4.28$ m/s
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.6 - Motion of a Projectile - Problems - Page 49: 75
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