Answer
The correct answer is (a) $7.5\times 10^{-4}~kg~m/s$.
Work Step by Step
$p = mv$
$p = (3\times 10^{-4}~kg)(2.5~m/s)$
$p = 7.5\times 10^{-4}~kg~m/s$
The correct answer is (a) $7.5\times 10^{-4}~kg~m/s$.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 271: 8.106
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