Answer
b) v_{x}= -7.07m/s
v_{y}= -42.1m/s
c)v=42.7m/s
\theta = 80.5^{\circ} South of West
Work Step by Step
b} v_{p/e}=v_{p/a} + v_{a/e}
v_{p/e} = (0,-35) + (-10cos45 , -10 sin45)
v_{p/e} = (-7.07, -42.1) m/s
Therefore, v_{x}= -7.07m/s
v_{y}= -42.1m/s
c)v =\sqrt x((-7.07)^{2}+ (-42.1)^{2})
v= 42.7m/s
\theta = 42.1/7.07 = 80.5 ^{\circ}
Therefore, \theta = 80.5 ^{\circ} South of West
