Answer
(a) $v = 2.99\times 10^4~m/s$
(b) $a_R = 5.96\times 10^{-3}~m/s^2$
(c) $v = 4.78\times 10^4~m/s$
$a_R = 3.95\times 10^{-2}~m/s^2$
Work Step by Step
(a) $v = \frac{2\pi ~r}{t} = \frac{(2\pi)(1.50\times 10^{11}~m)}{(365\times 24 \times 3600~s)} = 2.99\times 10^4~m/s$
(b) $a_R = \frac{v^2}{R} = \frac{(2.99\times 10^4~m/s)^2}{1.50\times 10^{11}~m} = 5.96\times 10^{-3}~m/s^2$
(c) $v = \frac{2\pi ~r}{t} = \frac{(2\pi)(5.79\times 10^{10}~m)}{(88.0\times 24 \times 3600~s)} = 4.78\times 10^4~m/s$
$a_R = \frac{v^2}{R} = \frac{(4.78\times 10^4~m/s)^2}{5.79\times 10^{10}~m} = 3.95\times 10^{-2}~m/s^2$
