University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 30: 1.53

Answer

a)A person breaths about 2200g of oxygen in a day. b)The length of each side of the tank is 2.1m.

Work Step by Step

Given:Density of air(d)=1.29$\frac{kg}{m^3}$ a)The number of breath a normal person takes in a minute in 12 breaths per minute. So in one day,the number of breaths =$12\times60\times24\frac{breaths}{day}$=17280$\frac{breaths}{day}$. Also,typically a person breath about $\frac{1}{2}L$ of air per breath Now,the mass of air a person breaths in a day ,m=density.volume m=$1.29\times\frac{1}{2}\times17280\times10^{-3}$kg [$since,1m^3=1000L$] =11.1kg Since ,20% of this air is oxygen,the mass of oxygen a person breaths in a day is $\frac{20}{100}\times11.1$kg=2.2kg=2200g b)The volume of the cubical tank,v=$x^3$ ,where x=length of each side of the cubical tank Now,the volume of air that a person breaths in a day is$\frac{1}{2}\times17280\times10^{-3}m^3$=8.64 $m^3$ If this air is stored uncompressed in a cubical tank ,then both their volumes are equal i.e, v=8.64$m^3$ $x^3=8.64m^3$ x=$\sqrt[3] 8.64$ m =2.1 m Therefore,the length of each side of the cubical tank is 2.1 m.
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