Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 98: 2-27E

Answer

$W=216000lbf*ft=277.57Btu$

Work Step by Step

Knowing that: $1ton=2000lbm$ Then: $W=mgh=(3*2000lbm)*(32.2\frac{ft}{s^2})*(36ft)*(\frac{1lbf}{32.2\frac{lbm*ft}{s^2}}=216000lbf*ft$ $216000lbf*ft*(\frac{1Btu}{778.17lbf*ft})=277.57Btu$
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