Answer
$Q_{dissipated}=345.23W$
Work Step by Step
The rate of heat supply by the fan motor to the room is the one that dissipates as heat and the one that move the fan wich eventually is dissipated as heat. Then all the electrical energy consumed is dissipated as heat:
$Q_{dissipated}=\frac{0.25hp*\frac{745.7W}{1hp}}{0.54}=345.23W$