Answer
$P_{1}=96.2kPa$
Work Step by Step
$P_{atm}=90kPa$
Solving the manometer:
$P_{atm}+\gamma_{B}*h_{B}+\gamma_{A}*h_{A}=P_{1}$
$P_{1}=90kPa+8\frac{kN}{m^3}*0.15m+100\frac{kN}{m^3}*0.05m$
$P_{1}=96.2kPa$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 1 - Introduction and Basic Concepts - Problems - Page 46: 1-79
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