Answer
$SG_{2}=1.34$
Work Step by Step
Solving the manometer:
$P_{air}+\rho_{1}*h_{1}*g-\rho_{2}*h_{2}*g=P_{atm}$
$P_{atm}-P_{air}=SG_{1}*\rho_{water}*h_{1}*g-SG_{2}*\rho_{water}*h_{2}*g$
Solving for $SG_{2}$
$SG_{2}=-[(\frac{P_{atm}-P_{air}}{\rho_{water}*g}-SG_{1}*h_{1}) \div h_{2}]$
$SG_{2}=-[(\frac{100000Pa-76000Pa}{(1000\frac{kg}{m^3})*(9.81\frac{m}{s^2})}-13.55*0.22m) \div 0.4m]$
$SG_{2}=1.34$
