Answer
(a) $213m$
(b) $52.5^{\circ}$
Work Step by Step
(a) We can find the required distance as follows:
$R=\frac{v_{\circ}^2}{g}sin2\theta$
We plug in the known values to obtain:
$R=\frac{(46.5)^2}{9.81}sin75.0^{\circ}=213m$
(b) We can find the required direction as
$\theta=90^{\circ}-37.5^{\circ}=52.5^{\circ}$
