Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1154: 68

Answer

(a) $neutron=142, protons=90$ (b) $neutron=129, protons=82$ (c) $neutron=33, protons=27$

Work Step by Step

(a) We can find the number of neutrons and protons in $Th^{232}_{90}$ as follows: $neutrons=Atomic\space mass-Atomic\space number =232-90=142$ and $protons=Atomic\space number=90$ (b) We can find the number of neutrons and protons in $Pb^{211}_{82}$ as follows: $neutrons=Atomic\space mass-Atomic\space number =211-82=129$ and $protons=Atomic\space number=82$ (c) We can find the number of neutrons and protons in $CO^{60}_{27}$ as follows: $neutrons=Atomic\space mass-Atomic\space number =60-27=33$ and $protons=Atomic\space number=27$
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