Answer
(a) $0.42rem$
(b) $0.023J$
Work Step by Step
(a) We can find the required dosage as
$Dose\space in \space rem=(Dose\space in\space rad)(RBE)$
$\implies Dose\space in \space rem=(0.032rad)(13)=0.42rem$
(b) The energy absorbed by the patient can be determined as
$E=(Dose\space in \space rad)m$
$E=(0.032rad)(\frac{0.01J/Kg}{1rad})72Kg$
$E=0.023J$
