Answer
Bill:
$x=3.0~m-(4.905~m/s^2)t^2$
Ted:
$x=1.0~m+(4.2~m/s)t-(4.905~m/s^2)t^2$
Work Step by Step
$x=x_0+v_0t+\frac{1}{2}at^2$
Bill:
$x_0=3.0~m$, $v_0=0$, $a=-g=-9.81~m/s^2$
$x=3.0~m+0t+\frac{1}{2}(-9.81~m/s^2)t^2$
$x=3.0~m-(4.905~m/s^2)t^2$
Ted:
$x_0=1.0~m$, $v_0=4.2~m/s$, $a=-g=-9.81~m/s^2$
$x=1.0~m+(4.2~m/s)t+\frac{1}{2}(-9.81~m/s^2)t^2$
$x=1.0~m+(4.2~m/s)t-(4.905~m/s^2)t^2$