Answer
$4.9~m/s$
Work Step by Step
We can determine the required speed as follows:
$h=48in$
$\implies h=48\times 2.54\times 10^{-2}m=1.22m$
Now $v_i=\sqrt{2gh}$
We plug in the known values to obtain:
$v_i=\sqrt{2(9.8m/s^2)(1.22m)}$
$v_i=4.9m/s$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 53: 73
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