Answer
(a) $32~m/s^2$
(b) Less than 8.0 cm. $x=4.0~cm$
Work Step by Step
(a) $x=16~cm=0.16~m$, $x_0=0$ (tongue inside the mouth), $v_0=0$, $t=0.10~s$
$x=x_0+v_0t+\frac{1}{2}at^2$
$0.16~m=0+0(0.10~s)+\frac{1}{2}a(0.10~s)^2$
$0.16~m=(0.005~s^2)a$
$a=\frac{0.16~m}{0.005~s^2}=32~m/s^2$
(b) Less than 8.0 cm.
$t=0.050~s$
$x=x_0+v_0t+\frac{1}{2}at^2$
$x=0+0(0.050~s)+\frac{1}{2}(32~m/s^2)(0.050~s)^2$
$x=0.04~m=4.0~cm$
