Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 50: 39

Answer

(a) Two (b) $3.8~s$ (c) $7.6~s$

Work Step by Step

(a) $a=\frac{\Delta v}{\Delta t}$. Rearrange the equation: $\Delta t=\frac{\Delta v}{a}$. So, time is directly proportional to the change of velocity. That is, if $\Delta v_{2}=2\Delta v_{1}$, then $\Delta t_{2}=2\Delta t_{1}$. (b) $\Delta t_{1}=\frac{\Delta v_{1}}{a}=\frac{v_{f}-v_{i}}{a}=\frac{0-16~m/s}{-4.2~m/s^{2}}=3.8~s$ (c) $\Delta t_{2}=\frac{\Delta v_{2}}{a}=\frac{v_{f}-v_{i}}{a}=\frac{0-32~m/s}{-4.2~m/s^{2}}=7.6~s$
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