Answer
The magnitude of the acceleration is $8.85~m/s^{2}$ to the west.
Work Step by Step
- The magnitude:
$a_{av}=\frac{\Delta v}{\Delta t}=\frac{115~m/s}{13.0~s}=8.85~m/s^{2}$
- The direction:
Velocity and acceleration point in opposite directions because the jet is decelerating. So, acceleration points to west.
