Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 16: 46

Answer

(a) $14~m/s^{2}\gt14~ft/s^{2}$. (b) $14~m/s^{2}=46~ft/s^{2}$. (c) $14~m/s^{2}= 1.8\times10^{5}~km/h^{2}$.

Work Step by Step

$1~m=3.281~ft$, $1000~m=1~km$ and $1~h=3600~s$ (a) $14~m/s^{2}\gt14~ft/s^{2}$ because $1~m\gt1~ft$ (b) $14~m/s^{2}= (14~m/s^{2})(\frac{3.281~ft}{1~m})=46~ft/s^{2}$ (c) $14~m/s^{2}= (14~m/s^{2})(\frac{1~km}{1000~m})(\frac{3600~s}{1~h})^{2}=1.8\times10^{5}~km/h^{2}$
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