Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 17 - Superposition - Exercises and Problems - Page 483: 6

Answer

$40\,Hz$

Work Step by Step

There are two full wavelengths in the string and the string length is given to be $2.0\,m$. $\implies \text{Wavelength } \lambda=1.0\,m$ $\text{Frequency } f=\frac{v}{\lambda}$ where $v$ is the wave speed. $\implies f=\frac{40\,m/s}{1.0\,m}=40\,Hz$
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