Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 17 - Superposition - Exercises and Problems - Page 483: 5

Answer

$20\,\text{m/s}$

Work Step by Step

From the figure, we see that $2.5\lambda = 50\,\text{cm}$, where $\lambda$ is the wavelength. $\implies \lambda=\frac{50\,\text{cm}}{2.5}=20\,\text{cm}=0.20\,\text{m}$ Wave speed $v=\lambda f$ where $f$ is the frequency. $\implies v=(0.20\,\text{m})(100\,Hz)=20\,\text{m/s}$
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