Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 9 - Rotational Dynamics - Problems - Page 245: 26

Answer

$M=228N$

Work Step by Step

We choose the axis of rotation to be at the knee joint. - The weight of the leg $W$ produces a clockwise (negative) torque. The lever arm is $(0.1m+0.15m)\cos30=(0.25m)\cos30$ - $M$ produces a counterclockwise (positive) torque. The lever arm is $(0.1m)\sin25$ The leg is in equilibrium, so these 2 torques balance each other. $$W(0.25m)\cos30=M(0.1m)\sin25$$ $$M=\frac{44.5N(0.25m)\cos30}{(0.1m)\sin25}=228N$$
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