Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 215: 61

Answer

The rear wheel makes $974$ revolutions.

Work Step by Step

We call the distance each wheel makes during the ride $d$. The wheels follow rolling motion, so we have - Front wheel: $d=s_{front}=r_{front}\theta_{front}$ - Rear wheel: $d=s_{rear}=r_{rear}\theta_{rear}$ Therefore, $$r_{front}\theta_{front}=r_{rear}\theta_{rear}$$ $$\theta_{rear}=\frac{r_{front}\theta_{front}}{r_{rear}}$$ $r_{front}=1.2m$, $r_{rear}=0.34m$ and $\theta_{front}=276rev\times(\frac{2\pi rad}{1rev})=1734.16rad$ Therefore, $$\theta_{rear}=6102.56rad\times\Big(\frac{1rev}{2\pi rad}\Big)=974\text{ revolutions}$$
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