Answer
a) $v=92.16m/s$
b) $\alpha=34.56rad/s^2$
Work Step by Step
a) We are given the wheel's angular speed $\omega=288rad/s$ and its radius $r=0.32m$
The dragster has a rolling motion, so the dragster's linear speed is $$v=v_T=r\omega=92.16m/s$$
b) The dragster starts from rest, so $v_0=0$. We also know the distance $s=384m$. We can find the linear acceleration of the dragster: $$a=\frac{v^2-v_0^2}{2s}=11.06m/s^2$$
Thanks to rolling motion, we also have $$a=a_T=r\alpha$$ $$\alpha=\frac{a}{r}=34.56rad/s^2$$
