Answer
The length of the rotating string is $0.183m$
Work Step by Step
We know $v_T=54m/s$ and $\omega=(47rev/s)\times\frac{2\pi rad}{1rev}=295.3rad/s$
The length of the rotating string is $$r=\frac{v_T}{\omega}=0.183m$$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 8 - Rotational Kinematics - Problems - Page 214: 37
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