Answer
a) $\omega=1.53\times10^3rad/s$
b) $t=4.1\times10^{-3}s$
Work Step by Step
We have $r=1.5\times10^{-8}m$ and $v_T=2.3\times10^{-5}m/s$
a) The angular speed of the bacterial motor is $$\omega=\frac{v_T}{r}=1.53\times10^3rad/s$$
b) To make one revolution, or a displacement $\theta=2\pi\ rad$, the time needed is $$t=\frac{\theta}{\omega}=4.1\times10^{-3}s$$
