Answer
$t=0.125s$
Work Step by Step
We have $\omega_0=3rev/s$, $\omega=5rev/s$ and displacement $\theta=0.5rev$
The amount of time the maneuver takes is $$\theta=\Big(\frac{\omega+\omega_0}{2}\Big)t$$ $$t=\frac{2\theta}{\omega+\omega_0}=0.125s$$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 8 - Rotational Kinematics - Problems - Page 213: 21
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