Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 213: 20

Answer

a) $\alpha=-22.06rad/s^2$ b) $t=0.68s$

Work Step by Step

The skater has initial velocity $\omega_0=+15rad/s$, final velocity $\omega=0$ and displacement $\theta=+5.1rad$ a) Her average angular acceleration is $$\omega^2=\omega_0^2+2\alpha\theta$$ $$\alpha=\frac{\omega^2-\omega_0^2}{2\theta}=-22.06rad/s^2$$ b) The time during which she comes to rest is $$t=\frac{\omega-\omega_0}{\alpha}=0.68s$$
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