Answer
0.557 m/s
Work Step by Step
We obtain:
$(Mc)(Vcox)+(Mmc)(Vmcox)= (Mc+Mmc)Vfx$
$150(.8)cos25^{\circ}+440(.5)=(150+440)Vfx$
$108.8+220=590Vfx$
$328.8/590=Vfx= 0.557 m/s$
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