Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 169: 69

Answer

$T=666.7N$

Work Step by Step

The formula for average power states that $$\overline P=\frac{W}{t}$$ $$W=\overline Pt$$ The difference between 2 cases is that when there is a skier behind, the engine must do more work to pull the skier, which is translated in the tension $T$ in the rope. In other words, - When there is no skier: $W_{other forces}=(7.5\times10^4)t$ - When there is a skier: $W_T+W_{other forces}=(8.3\times10^4)t$ From these 2 equations, we can see that $$W_T=(8.3\times10^4)t-(7.5\times10^4)t=(0.8\times10^4)t (1)$$ Next, we know $W_T=(T\cos\theta)s$ $T$ acts as the force pulling the skier along the movement, so $\cos\theta=\cos0=1$ The distance traveled $s=v_{avg}t=12t$ So, $W_T=12Tt$ Plug this back to (1), we can calculate $T$: $$T=\frac{0.8\times10^4}{12}=666.7N$$
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