Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 169: 52

Answer

The work done by air resistance is $-3.79J$.

Work Step by Step

When there is air resistance, the energies are not conserved, so according to the work-energy theorem: $$W_{nc}=E_f-E_0$$ $$\Big(\frac{1}{2}mv_f^2+mgh_f\Big)-\Big(\frac{1}{2}mv_0^2+mgh_0\Big)=W_{air}$$ $$\frac{1}{2}m(v_f^2-v_0^2)+mg(h_f-h_0)=W_{air}$$ We take the starting point of the ball to be the moment when the ball is released and the finish point to be the moment it goes through the net. We have $h_f=3.1m$, $h_0=2m$, $v_f=4.2m/s$, $v_0=7.2m/s$ and $m=0.6kg$, so $$W_{air}=-3.79J$$
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