Answer
5.24 $\times$ $10^{5}$ J
Work Step by Step
$\Delta$h = 2830sin(14.6$^{\circ}$)
$\approx$ 713.36 m
$E_{GP}$ = mg$\Delta$h
= 75(9.8)(713.36)
$\approx$ 5.24 $\times$ $10^{5}$ J
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 6 - Work and Energy - Problems - Page 167: 29
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