Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 139: 36

Answer

$T=1.44\times10^4s=4hr$

Work Step by Step

We have $M_E=5.98\times10^{24}kg$ and $G=6.67\times10^{-11}Nm^2/kg^2$ The radius of the orbit $r=2r_E=2\times6.38\times10^6=1.276\times10^7m$ The period of the satellite is $$T=\frac{2\pi r^{3/2}}{\sqrt{GM_E}}=1.44\times10^4s=4hr$$
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