Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 139: 33

Answer

$v_2=1.33\times10^4m/s$

Work Step by Step

We take the planet's mass to be $M$. Satellite 1 has $v_1=1.7\times10^4m/s$ and $r_1=5.25\times10^6m$ Satellite 2 has $r_2=8.6\times10^6m$ From the formula to find orbital speed $v=\sqrt{\frac{GM}{r}}$, we have $$\frac{v_2}{v_1}=\sqrt{\frac{\frac{GM}{r_2}}{\frac{GM}{r_1}}}=\sqrt{\frac{r_1}{r_2}}=0.78$$ $$v_2=0.78v_1=1.33\times10^4m/s$$
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