Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 26 - The Refraction of Light: Lenses and Optical Instruments - Problems - Page 758: 15

Answer

$2.46\times10^{8}m/s$

Work Step by Step

Recall that index of refraction $n= \frac{sin i}{sin r}=\frac{c}{v}$ where i is the angle of incidence, r is the angle of refraction, c is the speed of light in air and v is the speed of light in the material. Thus, we find: $\frac{sin 63.0^{\circ}}{sin 47.0^{\circ}}=\frac{3.00\times10^{8}m/s}{v}$ $⇒v=\frac{3.00\times10^{8}m/s\times sin 47.0^{\circ}}{sin 63.0^{\circ}}$ $=2.46\times10^{8}m/s$
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