Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 574: 37

Answer

21 V

Work Step by Step

$\overline{P}=\frac{V_{rms}^{2}}{R}\implies V_{rms}=\sqrt {\overline{P}\times R}$ $=\sqrt {55\,W\times4.0\,\Omega}=15\,V$ Thus, it follows: $V_{0}=V_{rms}\times \sqrt 2=15\,V\times\sqrt 2=21\,V$
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