Answer
(a) 786 W
(b) 1572 W
Work Step by Step
$I_{rms}=6.50\,A$
$R=18.6\,\Omega$
(a) Average power $\overline{P}=I_{rms}^{2}\times R=(6.50\,A)^{2}\times18.6\,\Omega=786\,W$
(b) Peak power $P_{0}=I_{0}V_{0}=2(\frac{1}{2}I_{0}V_{0})=2\overline{P}=2\times786\,W=1572\,W$
