Answer
1.70 s
Work Step by Step
$x=vt-\frac{1}{2}at^{2}$
$(25.0+59.7)=(45.0)t-\frac{1}{2}(-5.70)t^{2}$
$84.7=45.0t+2.85t^{2}$
$2.85t^{2}+45.0t-84.7=0$
Using the quadratic formula:
$t=\frac{-(45.0)±\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}$
$t\gt0$ hence
$t=\frac{-(45.0)+\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}\approx 1.70s$
