Answer
Acceleration is $3.1\; m/s^{2}$ south
Work Step by Step
Let north be the positive direction.
$v^{2}=u^{2}+2ax$
$a=\frac{v^{2}-u^{2}}{2x}=\frac{(6.1)^{2}-(69)^{2}}{2(750)}\approx-3.1\; m/s^{2}$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 29
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