Answer
$\therefore$ the pressure gauge attached to his wrist will register this drop in air pressure
Work Step by Step
P2 = P1 + ρgh
In the above relation, the pressure at a given point depends on the vertical distance h.
Here P2 = Pressure at depth of h (i.e on the wrist of a scuba driver).
P1 = Pressure on the surface.
Since, when the strom approches $P_1$ $\downarrow$
from the above relation $P_2$ $\downarrow$
Hence, the pressure gauge attached to his wrist will register this drop in air pressure
